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CGP EDU Academic Team
Published on: August 14, 2026
200 mL of 0.2 M HCl is mixed with 300 mL of 0.1 M NaOH. The molar heat of neutralization of this reaction is −57.1 kJ. The increase in temperature in ∘ C of the system on mixing is x × 10 −2 . The value of x is ____. (Nearest integer)[Given : Specific heat of water = 4.18 J g −1 K −1
Density of water = 1.00 g cm −3 ] (Assume no volume change on mixing)
Text Solution
Verified by ExpertsThe correct answer is:
82
(82)
⇒ Millimoles of HCl = 200 × 0.2 = 40
⇒ Millimoles of NaOH = 300 × 0.1 = 30
⇒ Heat released 
⇒ Mass of solution = 500ml × 1gm/ml = 500gm
= 81.96 × 10 −2 K
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