Home Chemistry Thermodynamics and Thermochemistry JEE Main 2020 (Thermodynamics) For water Δ vap H = 41 kJ mol −1 at 373 K an…
Chemistry Thermodynamics and Thermochemistry JEE Main 2020 (Thermodynamics) Numeric Response
Published on: August 14, 2026

For water Δ vap H = 41 kJ mol −1 at 373 K and bar pressure. Assuming that water vapour is an ideal gas thatoccupies a much larger volume than liquid water, the internal energy change during evaporation of water is____ kJmol −1 [Use : R = 8.3 J mol −1 K −1 ]

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
38

(38)

Given equation is

From the reaction :

⇒ DU = 41 − 3.0959

= 38 kJ/mol

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.