(i), (ii) and (iii) by appropriately matching the information given in the three columns of the following table.
Electrons are filled in orbitals following Auf-bau rule, Paulli exclusion principle and Hund's rule of maximum multiplicity. | ||
Column 1 | Column 2 | Column 3 |
(I) Cu+ | (i) Number of unpaired electrons are 4 | (P) Magnetic moment is B.M. |
(II) Fe+3 | (ii) Number of electron related to | (Q) Number of electrons related to n + λ=5 are 6. |
(III) Cr+3 | (iii) Total spin = | (R) Number of electrons to |
(IV) Co+3 | (iv) Number of electrons related to | (S) Magnetic moment is B.M. |
(i) Ion which have maximum number of full filled orbital then the only correct combination is
Text Solution
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(i)A
Cu + ⎯→ 1s 2 , 2s 2 , 2p 6 , 3s 2 , 3p 6 , 3d 10
Fe +3 ⎯→ 1s 2 , 2s 2 , 2p 6 , 3s 2 , 3p 6 , 3d 5
Cr +3 ⎯→ 1s 2 , 2s 2 , 2p 6 , 3s 2 , 3p 6 , 3d 3
Co +3 ⎯→ 1s 2 , 2s 2 , 2p 6 , 3s 2 , 3p 6 , 3d 6
Cu + ion have maximum number of full filled orbital
Number of electrons related to λ = 2 are 10
Number of electrons related to λ + m = 0 are 12
(ii)C
Cr +3 ⎯→ 1s 2 , 2s 2 , 2p 6 , 3s 2 , 3p 6 , 3d 3 Number of electrons related to n + λ = 5 are 3
Magnetic moment u = 
B.M. = 
= 
B.M.
(iii)D
Co
+3 ⎯→ 1s 2 , 2s 2 , 2p 6 , 3s 2 , 3p 6 , 3d 6 Number of unpaired e
– = 4
Number of electrons related to n + λ = 5 are 6.
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