Published by:
CGP EDU Academic Team
Published on: August 13, 2026
As Rhombic sulphur is heated in a test tube :
Process | Temperature | |
(a) | Viscosity increases | T1 |
(b) | Viscosity decreases | T2 |
(c) | Paramagnetic molecules | T3 |
(d) | Breakage of S8 rings | T4 |
(Diradical formation in molten phase) |
Correct order of temperature is :
Text Solution
Verified by ExpertsThe correct answer is:
C
When sulphur is heated, firstly S 8 rings break, diradicals are formed, polymerisation takes place. On further T viscosity increase and then viscosity decrease at very high temperature (~ 600ºC) rings are formed and in vapour phase S 2 (paramagnetic) molecules are present.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Covalency of oxygen cannot exceed 2 unlike sulphur which can show +4 or +6 because
Why do alkali metals form unipositive ions and impart characteristic colours to flame?
Comment on the order of mobilities of the alkali metal ions in aqueous solution : Li + < Na + < K +…
Why is KO 2 paramagnetic ?
Draw the structure of BeCl 2 in solid and vapour state.
Explain why in anion of Na 2 CO 3 all bond lengths are equal ?