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CGP EDU Academic Team
Published on: August 13, 2026
In the reaction : 2Al + Cr 2 O 3 
Al 2 O 3 + 2Cr, 49.8 g of Al reacted with 200.0 g Cr 2 O 3 . How much grams of reactant remains at the completion of the reaction ?
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(60 )
(Atomic weight of Al and Cr = 27 and 52, M.wt. of Cr 2 O 3 = 152)
Moles of Al = 
= 18.4 mol
= 
= 9.2 mol of Cr 2 O 3
Moles of Cr 2 O 3 = 
= 1.31 mol
Since 2 mol Al is required for 1 mol of Cr 2 O 3 .
So, Al is the limiting reagent and Cr 2 O 3 is in excess. Moles of Cr 2 O 3 is excess
= (1.31 – .92) = 0.4 mol
Weight of excess Cr 2 O 3 = 0.4 × 152 = 60 g Cr 2 O 3
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