A fluorine disposal plant was constructed to carryout the reactions :
F 2 + 2NaOH 
O 2 + 2NaF + H 2 O
2NaF + CaO + H 2 O 
CaF 2 + 2NaOH
As the plant operated, excess lime was added to bring about complete precipitation of the fluoride as CaF 2 . Over a period of operation, 1900 kg of fluorine was fed into a plant and 10,000 kg of lime was required. What was the percentage utilization of lime ? [Lime :CaO]
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(28)
F 2 + 2NaOH ⎯→ 
O 2 + 2NaF + H 2 O
Mole 50 × 10 3 2[50 × 10 3 ]
2NaF + CaO + H 2 O ⎯→ CaF 2 + 2 NaOH
2× [50 × 10 3 ] 50 × 10 3 Mole
Weight of lime (CaO) = 50 × 10 3 × 56
= 2800 kg.
Feed amount of lime = 10,000
% Utilization = 
× 100 = 28%
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