Published by:
CGP EDU Academic Team
Published on: August 13, 2026
A 3 : 2 molar ratio mixture of FeO and Fe 2 O 3 react with oxygen to produce a 2 : 3 molar ratio mixture of FeO and Fe 2 O 3 . Find the mass (in g) of O 2 gas required per mole of the initial mixture
Text Solution
Verified by ExpertsThe correct answer is:
2
(2)
From one mole of initial mixture, some FeO must have reacted with oxygen and got converted into Fe 2 O 3 .
4FeO + O 2 
2Fe 2 O 3
Initial moles 
Final moles 
– x 
+ 
But, final moles ratio is 2 : 3.
∴ 
= 
∴ x = 
∴ Moles of FeO reacted = x = 
∴ Moles of O 2 required = 
(x) = 
= 0.0625
∴ Mass of O 2 required = 0.0625 × 32 = 2 g
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