Calculate the equilibrium constant for the reaction : H 2 (g) + CO 2 (g) 
H 2 O(g) + CO(g)
at 1395 K, if the equilibrium constants at 1395 K for the following are
2H 2 O(g) 
2H 2 (g) + O 2 (g) K 1 = 2.1 × 10 –13
2CO 2 (g) 
2CO(g) + O 2 (g) K 2 = 1.4 × 10 –12 .
1395 K ij H 2 (g) + CO 2 (g) 
H 2 O(g) + CO(g)
Text Solution
Verified by Experts2
(2.58 )
H 2 (g) + CO 2 (g) 
H 2 O (g) + CO (g).
2H 2 O (g) 
2H 2 (g) + O 2 (g) K 1 = 2.1 × 10 –13 ....
2CO 2 (g) 
2CO(g) + O 2 (g) K 2 = 1.4 × 10 –12 ....
eq. – 
eq.
CO 2 (g) – H 2 O (g) 
CO (g) + 
O 2 (g) – H 2 – 
O 2 (g).
CO 2 (g) + H 2 (g) 
H 2 O (g) + CO (g).
[eq. – eq. ]
K = 
= 
= 
= 2.58. Ans.
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