Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The homogeneous reversible reaction, C 2 H 5 OH + CH 3 COOH
CH 3 COOC 2 H 5 + H 2 O is studied at various initial concentrations of the reactants at constant temperature. Calculate initial acid and alcohol moles.
Moles of acid per liter (initial) | Moles of alcohol per liter (initial) | Moles of ester per liter at equilibrium | |
(i) | 1 | 1 | 0.667 |
(II) | X | Y | 8/3 |
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(X = 4, Y = 4)
From experiment (i):


For experiment (ii) :


Taking equal values,


Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
For the system ⇌ , the expression for equilibrium constant is
In the reversible reaction ⇌ , the concentration of each C and D at equilibrium was 0.8 mole/litr…
4 moles of A are mixed with 4 moles of B. At equilibrium for the reaction ⇌ , 2 moles of C and D …
On a given condition, the equilibrium concentration of and are 0.80, 0.10 and 0.10 mole/litre. Th…
In which of the following, the reaction proceeds towards completion
A reversible chemical reaction having two reactants in equilibrium. If the concentrations of the re…