K p is 9 atm 2 for the reaction: LiCl.3NH 3 (s) 
LiCl.NH 3 (s) + 2NH 3 (g) at 40°C. How many moles of ammonia must be added at this temperature to a 5 litre flask containing 0.1 mole of LiCl. NH 3 in order to completely convert the solid to LiCl.3NH 3 ? Multiply the obtained answer by 100. Round off the answer to the nearest integer.
Text Solution
Verified by Experts0.7844
(78 mole)
LiCI. 3NH 3 (s) 
LiCI. NH 3 (s) + 2NH 3 (g) K p = 9 atm 2 = p 2 NH3
0.1 a 
p NH3 = 3 atm
no. of moles of NH 3 at equilibrium = 
= 0.5844
For 0.1 mol of LiCI NH 3 to convent 0.2 mol of NH 3 must be needed.
Total number of mol of NH 3 req. = 0.7844
Answer : 0.7844 × 100 = 78.44
After rounding of Answer is 78.
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