Published by:
CGP EDU Academic Team
Published on: August 12, 2026
Solid A and B are taken in a closed container at a certain temperature. These two solids decompose and following equilibria are established simultaneously
A(s) 
X(g) + Y(g) 
= 250 atm 2
B(s) 
Y(g) + Z(g) 
= ?
If the total pressure developed over the solid mixture is 50 atm. Then the value of K P for the 2 nd reaction.
Text Solution
Verified by ExpertsThe correct answer is:
A
A(s) 
X + Y
α α + β
B(s) 
Y + Z
β + α β
⇒ 
= α ( α + β )
= β ( α + β )
P total = ( α + β ) + α + β = 2 ( α + β )
⇒ 2 ( α + β ) = 50 ⇒ α + β = 25
⇒ 250 = 25 α ⇒ α = 10 , β = 15
⇒ 
= β ( α + β ) = 15 × 25 = 375
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