Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Two solid compounds A and C dissociate into gaseous product at temperature T as follows :
(i) A(s)
B(g) + D(g) Kp 1 = 625 (atm) 2
(ii) C(s)
E(g) + D(g) Kp 2 = 975 (atm) 2
Both solid are present in same container then calculate total pressure over the solid mixture.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(80 atm)
A(s)
+
Kp 1 = 625
C(s)
+
Kp 2 = 975
Kp 1 + Kp 2 = (
+
+ 2p 1 p 2 ) = (p 1 + p 2 ) 2 = (625 + 975) ⇒ (p 1 + p 2 ) = 40
so total pressure = 2[p 1 + p 2 ] = 80 atm.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
In a two litre capacity flask 4 gm hydrogen and 50.8 gm. Iodine were present at 673 K. Calculate th…
Equilibrium constants is given (in atm) for the following reaction 0ºC :
Na 2 HPO 4 .12H 2 O(s) Na…
Match the following : (Assume only reactants were present initially).
Column-ΙColumn-ΙΙ(a)N2(g) + 3…
Column-I (Assume only reactant were present initially)Column-II(a) For the equilibrium NH4Ι(s) NH3…
A 10 liter box contains O 3 and O 2 at equilibrium at 2000 K. K P = 4 × 10 14 atm for 2O 3 (g) 3O …
If for 2A 2 B(g) 2A 2 (g) + B 2 (g), K p = TOTAL PRESSURE (at equilibrium) and starting the dissoc…