Published by:
CGP EDU Academic Team
Published on: August 14, 2026
If a mixture 0.4 mole H 2 and 0.2 mole Br 2 is heated at 700 K at equilibrium, the value of equilibrium constant is 0.25 × 10 10 then find out the ratio of concentrations of (Br 2 ) and (HBr) (Report your answer as 
× 10 11 )
Text Solution
Verified by ExpertsThe correct answer is:
80
(80)
H 2 + Br 2 
2HBr
t = 0 0.4 0.2 –
t = t eq. 0.2 y 0.4
= negligible x.; = y
× 10 10 = 
y = 3.2 × 10 –10
× 10 11 = 
× 10 –10 × 10 11 = 80
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