Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Calculate the work done during isothermal reversible expansion of one mole ideal gas from 10 atm to 1 atm at 300 K.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(– 5744.4 J)
Given that:
P 1 = 10 atm, P 2 = 1 atm, T = 300 K, n = 1
R = 8.314 J/K/mol
Now, by using
W = – 2.303 nRT log 10 
= –2.303 × 1 × 8.314 × 300 log 10 
W = –5744.1 Joule
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