An ideal gas in a thermally insulated vessel at internal pressure = P 1 , volume = V 1 and absolute temperature = T 1 expands irreversibly against zero external pressure, as shown in the diagram. The final internal pressure, volume and absolute temperature of the gas are P 2 , V 2 and T 2 , respectively. For this expansion,
= 
Text Solution
Verified by ExpertsA
(a,b,c)
Since the vessel is thermally insulated so
q = 0
p ext = 0 , so w = 0
so Δ U = 0 (ideal gas)
Hence Δ T = 0
⇒ Δ T = 0
⇒ T 2 = T 1
⇒ P 2 V 2 = P 1 V 1
The process is however adiabatic irriversible.
So we cannot apply P 2 V 2 γ = P 1 V 1 γ
Hence ans is , ,
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