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CGP EDU Academic Team
Published on: August 13, 2026
The equilibrium constant for a reaction is 10. What will be the magnitude value of Δ Gº ?
R = 8.31 JK –1 mol –1 , T = 314 K. (Approximate integer value in KJ mol –1 )
Text Solution
Verified by ExpertsThe correct answer is:
6
(6)
Given : K eq = 10
T = 314 K
Δ Gº = – 2.303 RT log K eq = – 2.303 × 8.31 × 314 log 10 J = – 6 kJ mol –1 .
Ans. The value of Δ Gº is –6 kJ mol –1 .
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