Match the column:
Columm-I | Columm-II | ||
(a) | Reversible adiabatic compression | (p) | ΔSsystem > 0 |
(b) | Reversible vaporisation of liquid | (q) | ΔSsystem < 0 |
(c) | 2N(g) ⎯→ N2(g) | (r) | ΔSsurrounding < 0 |
(d) | MgCO3(s) MgO(s) + CO2(g) | (s) | ΔSsurrounding = 0 |
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
→ (s); → (p, r); → (q); → (p, r)
For reversible process Δ S universe = 0 and for adiabatic process Δ S system = 0
For reversible process Δ S universe = 0, and in vaporisation entropy of system increases
Number of gaseous moles decreases. So, entropy of system decreases and N 2 is more stable. So, process is spontaneous. For spontaneous process Δ S universe > 0
Number of gaseous moles increases. So, entropy of system increases
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