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CGP EDU Academic Team
Published on: August 14, 2026
Calculate the magnitude of free energy in KJ mol –1 when 1 mole of an ionic salt MX (s) is dissolved in water at 27°C. Given
Lattice energy of MX = 780 kJ mol –1
Hydration energy of MX = – 775.0 kJ mol –1
Entropy change of dissolution at 27°C = 40 J mol –1 K –1
Text Solution
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CHECK THE SOLUTION.
(7 kJ mol –1 .)
Δ H dissolution = Δ H ionisation + Δ H hydration = 780 – 775 = 5 kJ mol –1
Δ G dissolution = Δ H dissolution – T Δ S dissolution = 5000 – 300 × 40 = – 7000 J = – 7 kJ mol –1
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