Observe the three columns in which column-1 represents molecule, column-2 represents bond orders while column-3 represents molecule properties. Properties of molecule explained by molecular orbital theory. Like megnatic nature, orbital mixing etc.
Column 1 | Column 2 | Column 3 |
(I) B2 | (i) Bond Order = 2 | (P) Diamagnetic in Nature |
(II) | (ii) Bond Order = 2.5 | (Q) SP Mixing Occure |
(III) F2 | (iii) Bond Order = 1 | (R) Paramagnetic in Nature |
(IV) C2 | (iv) Bond Order = 3 | (S) Highest Occupied Molecular orbital (HOMO) is Bonding Molecular orbital (BMO) |
(i) Which is incorrect combination?
Text Solution
Verified by ExpertsB
(i)b (ii)c (iii)d
Sol. B 2 → (10 e) 
< 
< 
< 
< 
< σ *2p z .
N b = 6 e, N a = 4 , B.O. = 
= 
= 1
And S.P. mixing occurs, Paramagnetic in nature, HOMO is BMO.
→ (15 e) 
< 
< 
< 
< 
< 
< ( 
= π *2p y ) < σ *2p z
N b = 10 e, N a = 5 , B.O. = 
= 
= 2.5
And no S.P. mixing occur, Paramagnetic in nature, HOMO is ABMO.
F 2 → (18 e) 
< 
< 
< 
< 
< 
< ( 
= 
) < σ *2p z
N b = 10 e, N a = 8 , B.O. = 
= 
= 1
And no S.P. mixing occur, Diamagnetic in nature, HOMO is ABMO
C 2 → (12 e) 
< 
< 
< 
< 
< σ *2p z .
N b = 8 e, N a = 4 , B.O. = 
= 
= 2
And S.P. mixing occur, Diamagnetic in nature, HOMO is BMO.
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