Match the orbital overlap figures shown in List-I with the description given in List-II and select the correct answer using the code given below the lists.
List-I | List-II | ||
P. | 1. | p–d π antibonding | |
Q. | 2. | d–d σ bonding | |
R. | 3. | p–d π bonding | |
S. | 4. | d–d σ antibonding |
Code :
P Q R S
Text Solution
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⎯→ It is d–d axial overlap in same phase, so d–d σ bonding.
⎯→ It is p & d lateral overlap in same phase, so it is p–d π bonding.
⎯→ It is p and d lateral overlap in opposite phase, so it is p–d π antibonding.
⎯→ It is d–d axial overlap in opposite phase, so it is d–d σ antibonding.
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