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CGP EDU Academic Team
Published on: August 14, 2026
The enthalpy change for the reaction of 50 mL of ethylene with 50.0 mL of H 2 at 1.5 atm pressure is Δ H = –0.31 KJ. What is the Δ E ?
Text Solution
Verified by ExpertsThe correct answer is:
A
C 2 H 4 + H 2 ⎯→ C 2 H 6
50 ml 50 ml 0
X X 50 ml
Δ H = Δ U + P ( Δ V)
– 0.31 = Δ U + 1.5 × 1.01 × 10 5 (– 50 × 10 –6 ).
Δ U = – 0.3024 kJ.
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