Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Calculate work done by 1 mole of Ideal gas expand isothermally and irreversibly from pressure of 5 atm to 2 atm against a constant external pressure of 1 atm at 300 K temperature.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(–0.7478 kJ )
= – 
W irr = –P ext [V 2 – V 1 ] = –P ext
= –P ext × nRT 
= –1 × 1 × .082 × 300
= –1 × .082 × 300 ×
= –7.38 L.atm = –747.8 J
W irr = –0.7478 KJ
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Match the column:
Columm-IColumm-II (a)Reversible isothermal expansion of an ideal gas(p)w = –2.303…
Match the column:
Column-IColumn-II(a)A process carried out infinitesimally slowly(p)Adiabatic(b)A …
How many statements are false ?
(i) Thermodynamics is concerned only with total energy of the syste…
How many of the following physical properties are extensive :
(i) Free energy (ii) vapour pressure
…
How many of the following are state function :
(i) Internal energy (ii) Heat
(iii) Enthalpy (iv) En…
Two moles of He gas ( γ = 5/3) are initially at temp 27ºC and occupy a volume of 20 litres. The gas…