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CGP EDU Academic Team
Published on: August 14, 2026
1 mole of CO 2 gas at 300 K is expanded under reversible adiabatic condition such that its volume becomes 27 times.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
T 2 = 100 K, w = – 5.016 KJ
T 1 V 1 γ – 1 = T 2 V 2 γ – 1
300 × V 1/3 = T 2 × (27 V) 1/3 ⇒ T 2 = 100 K
( b) Δ E = q + W
For reversible adiabatic process,
q = 0
Δ U = W
⇒ W = n C V Δ T
⇒ W = 1 × 25.08 × (100 – 300) = – 5.016 kJ
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