For reduction of ferric oxide by hydrogen, Fe 2 O 3 (s) + 3 H 2 (g) ⎯→ 2 Fe(s) + 3 H 2 O( λ ) ;
Δ Hº 300 = − 26.72 kJ. The reaction was found to be too exothermic. To be convenient, it is desirable that Δ Hº should be at the most − 26 kJ . At what temperature difference it is possible ? C P [Fe 2 O 3 ] = 105, C P [Fe(s)] = 25, C P [H 2 O( λ )] = 75, C P [H 2 (g)] = 30 (all are in J/mol)
Text Solution
Verified by Experts9
(9)
Fe 2 O 3 (s) + 3 H 2 (g) ⎯→ 2 Fe(s) + 3 H 2 O(l)
Δ H° 300 K = –35 kJ
Δ H° = – 26 KJ
Δ C P = 2C P (Fe, s) + 3C P (H 2 O, λ ) – C P (Fe 2 O 3 , s) – 3C P (H 2 , g)
Δ C P = 80
– 26 × 10 3 = – 80 × 26720 + 80 ( Δ T)
Δ T = 9
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems