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CGP EDU Academic Team
Published on: August 14, 2026
5 moles of a liquid L are converted into its vapour at its boiling point (273°C) and at a pressure of 1 atm. If the value of latent heat of vapourisation of liquid L is 273 L atm/mole, then which of the following statements is/are correct : Assume volume of liquid to be negligible and vapour of the liquid to behave ideally
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a,b,c) 1 × V f = 5 × R × 546 = 224 L
W = – P ext ( Δ V) = – 1 atm (224 L) = – 224 L atm
∴ work done by system = 224 L atm
Enthalpy change ( Δ H) = q = 273 × 5 = 1365 L atm
Δ U = q + W = 1365 – 224 = 1141 L atm.
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