Select the correct enthalpy at corresponding temperature using following datas
(i) Heat capacity of solid from 0 K to normal melting point 200 K
C P,m (s) = 0.035 T JK –1 mol –1 .
(ii) Enthalpy of fusion = 7.5 KJ mol –1 ,
(iii) Enthalpy of vaporisation = 30 KJ mol –1
(iv) Heat capacity of liquid form 200 K to normal boiling point 300 K
C P,m ( λ ) = 60 + 0.016 T JK –1 mol –1 .
(v) Heat capacity of gas from 300 K to 600 K at 1 atm
C P,m (g) = 50.0 JK –1 mol –1 .
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(a,b,c,d)
S 200 =
= 7 J mol –1 K –1
S 200 ( l ) = 7 +
= 44.5 J mol –1 K –1 S 300 ( l ) = 44.5 +
= 44.5 + 60 ln
+ 1.6 = 70.43 J mol
–1 K –1 S 300 (g) = 70.43 +
= 170.43 J mol
–1 K –1
S 600 (g) = 170.43 + 50 ln
= 205.09 JK –1 mol –1
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