A sample of AgCl was treated with 5 mL of 1.6 M Na 2 CO 3 solution to give Ag 2 CO 3 . The resulting solution contained 0.00284 g of Cl – per litre. Determine K sp (AgCl), if K sp (Ag 2 CO 3 ) = 8.1 × 10 –12 . (Assume no hydrolysis of any ion).
Text Solution
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The concerned chemical reaction is :
2 AgCl + Na 2 CO 3 ⎯→ Ag 2 CO 3 + 2 NaCl
Calculation of [Ag + ] left in the solution :
K sp (Ag 2 CO 3 ) = [Ag + ] [CO 3 2– ]
[Ag + ] = 
= 2.25 × 10 –6 M
Concentration of Cl – left = 0.00284 g/L = 
mol/L = 8 × 10 –5 M
∴ K sp (AgCl) = [Ag + ] [Cl – ] = (2.25 × 10 –6 ) (8 × 10 –5 ) = 1.8 × 10 –10 .
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