An electrochemical cell is constructed with an open switch as shown below :
When the switch is closed, mass of tin-electrode increase. If Eº (Sn 2+ / Sn) = – 0.14 V and for Eº (X n+ / X) = – 0.78 V and initial emf of the cell is 0.65 V, determine n and indicate the direction of electron flow in the external circuit.
Text Solution
Verified by Experts0.65
n = 3, Since mass of Sn increasing, Sn - electrode is working as cathode and X - metal electrode anode and electrons are flowing from X-electrode to Sn-electrode in the external circuit.
Sol. 0.65 = E oxid + E red = 
+ 
0.01 = – 
× (– 1) – 
× 0.301= 0.0591 
n = 3
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