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CGP EDU Academic Team
Published on: August 14, 2026
Equinormal Solutions of two weak acids, HA (pK a = 3) and HB (pK a = 5) are each placed in contact with standard hydrogen electrode at 25°C (T = 298 K). When a cell is constructed by interconnecting them through a salt bridge find the e.m.f. of the cell.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
E = 0.059 V
Sol. Pt / H 2 O / H + (HA) // H + (HB) / H 2 / Pt
H 2 ⎯→ 2H + + 2e –
2H + +2e – ⎯→ H 2
2H + (HB) ⎯→ 2H + HA Eº = 0
E = 0 – 
log 
But Ka = 
= – 
log 
= – 0.0591
the cell is constructed in reversed direction
E cell = 0.0591 volt.
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