Explain the following with proper reason :
(i) Bleaching of flowers by chlorine is permanent while after bleaching with SO 2 , the colour returns.
(ii) Iodine dissolves more in K Ι solution than in water.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i) Chlorine bleaching action is due to oxidation while that of sulphur dioxide is due to reduction. Hence, the substance bleached by SO 2 is reoxidised by the oxygen of the air to its original state.
Cl 2 bleaches coloured material by oxidation and thus bleaching is permanent.
Cl 2 + H 2 O ⎯→ 2HCl + [O]
Coloured material + [O] ⎯→ Colourless
On the other hand beaching by SO 2 is by reduction and thus temporary because colourless articles are further oxidised by air.
SO 2 + 2H 2 O ⎯→ 2H 2 SO 4 + 2[H]
Coloured material + [H] ⎯→ Colourless
coloured
(ii) Ι 2 is a covalent molecule. Thus, its solubility is less in polar solvent, i.e., water. Potassium iodide combines with iodine and forms a polyhalide which is an ionic compound. Being ionic, K Ι 3 is more soluble.
K Ι + Ι 2
K Ι 3 (K + Ι 3 – ) brown solution
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems