Chemistry Solution & Colligative Properties JEE Advanced Previous Years Question Single Correct MCQ
Published on: August 14, 2026

Two 5 molal solutions are prepared by dissolving a non-electrolyte non-volotatile solute separately in the solvents X and Y. The molecular weights of the solvents are M X and M Y , respectively where M X = M Y . The relative lowering of vapour pressure of the solution in X is "m" times that of the solution in Y. Given that the number of moles of solute is very small in comparison to that of solvent, the value of "m" is :

A
B
C
D

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The correct answer is:
B

Mol fraction in x solvent

x solute =

mol fraction in Y solvent

x solute =

Ratio of RLVP in both solutions

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