Co 2+ (aq.) + SCN – (aq.) 
Complex (X).
Ni 2+ (aq.) + Dimethylglyoxime 
Complex (Y).
The corrdination number of cobalt and nickel in complexes X and Y are four.
(i) The IUPAC names of the complexes (X) and (Y) are respectively :
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i) (X) = [Co(SCN) 4 ] 2– ; (Y) = [Co(dmg) 2 ].
(ii) X = [Co(SCN) 4 ] 2– , cobalt is in + 2 oxidation state and SCN – is weak field ligand. So ,
[Co(SCN) 4 ] 2– : 
(tetrahedral)
Y = [Ni(dmg) 2 ] : Nickel is in +2 oxidation state and dmg is chelating ligand. So,
[Ni(dmg) 2 ] : 
(square planar
(iii) X = [Co(SCN) 4 ] 2– , cobalt is in + 2 oxidation state and SCN – is weak field ligand. So ,
[Co(SCN) 4 ] 2– : 
(tetrahedral)
Y = [Ni(dmg) 2 ] : Nickel is in +2 oxidation state and dmg is chelating ligand. So,
[Ni(dmg) 2 ] : 
(square planar)
[Ni(dmg) 2 ] shows intra molecular H-bonding as shown below.
Reactions involved :
Co 2+ (aq) + 4SCN – (aq) [Co(SCN) 4 ] 2– (aq.) blue colour complex.
Ni 2+ (aq) + 2 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems