The vapour pressure of 30% (w/v), aqueous solution of glucose is________mm Hg at 25°C.
[Given: The density of 30% (w/v), aqueous solution of glucose is 1.2 g cm -3 and vapour pressure of pure water is 24 mm Hg.] (Molar mass of glucose is 180 g mol -1 )
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(23) To calculate the vapour pressure of the 30% (w/v) aqueous solution of glucose, we can use Raoult's law, which states that the vapour pressure of a component in an ideal solution is directly proportional to its mole fraction in the solution.
Weight of solution = 100 x 1. 2 = 120 gm
Weight of water = 120 - 30 = 90 gm Now using formula
24 x 90 - P x 90 = 3 P
P = 23.22
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