Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The value of log 10 K for a reaction A 
B is:
(Given: Δ r Hº 298 K = –54.07 kJ mol –1 , Δ r Sº 298 K = 10 JK –1 mol –1 and R = 8.314 JK –1 mol –1 ; 2.303 × 8.314 × 298 = 5705)
Text Solution
Verified by ExpertsThe correct answer is:
B
Δ Gº = Δ Hº – T Δ Sº = – 54.07 × 1000 – 298 × 10 = – 54070 – 2980 = – 57050
Δ Gº = – 2.303 RT log 10 K
– 57050 = – 2.303 × 298 × 8.314 log 10 K = – 5705 log 10 K
log 10 K = 10
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