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CGP EDU Academic Team
Published on: August 14, 2026
The combustion of benzene (I) gives CO 2 (g) and H 2 O(l). Given that heat of combustion of benzene at constant volume is –3263.9 kJ mol –1 at 25ºC; heat of combustion (in kJ mol –1 ) of benzene at constant pressure will be: (R = 8.314 JK –1 mol –1 )
Text Solution
Verified by ExpertsThe correct answer is:
B
C 6 H 6(liq) + 7.5 O 2(g) ⎯→ 6CO 2(g) + 3H 2 O (liq)
Δ n (g) = 6 – 7.5 = –1.5
Δ H = Δ E + Δ n (g) RT
Δ H = –3263.9kJ – 
= –3267.6 kJ
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