A series LCR circuit is connected to a 45 sin ( 
t) Volt source. The resonant angular frequency of the circuit is 10 5 rad s -1 and current amplitude at resonance is I 0 . When the angular frequency of the source is 
= 8 x 10 4 rad s -l , the current amplitude in the circuit is 0.05 I 0 . If L = 50 mH, match each entry in List-I with an appropriate value from List-II and choose the correct option.
List-I List-II
(P) I 0 in mA (1) 44.4
(Q) The quality factor of the circuit (2) 18
(R) The bandwidth of the circuit in rad s -1 (3) 400
(S) The peak power dissipated at resonance in Watt (4) 2250
(5) 500
2, Q 
3, R 
5, S 
1
3, Q 
1, R 
4, S 
2
4,Q 
5,R 
3,S 
l
4,Q 
2,R 
l,S 
5
Text Solution
Verified by ExpertsB
V = 45 sin 
t, L = 50 mH
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