A thin conducting rod MN of mass 20 gm, length 25 cm and resistance 10 
is held on frictionless, long, perfectly conducting vertical rails as shown in the figure. There is a uniform magnetic field B 0 = 4 T directed perpendicular to the plane of the rod-rail arrangement. The rod is released from rest at time t = 0 and it moves down along the rails. Assume air drag is negligible. Match each quantity in List-I with an appropriate value from List-II, and choose the correct option. [Given: The acceleration due to gravity g = 10 ms -2 and e -l = 0.4]
List-I List-II
(P) At t = 0.2 s, the magnitude of the induced emf in Volt (1) 0.07
(Q) At t = 0.2 s, the magnitude of the magnetic force in Newton (2) 0.14
(R) At t = 0.2 s, the power dissipated as heat in Watt (3) 1.20
(S) The magnitude of terminal velocity of the rod in m s -1 (4) 0.12
(5) 2.00
5, Q 
2, R 
3, S 
1
3, Q 
1, R 
4, S 
5
4,Q 
3,R 
l,S 
2
3, Q 
4,R 
2,S 
5
Text Solution
Verified by ExpertsD
From force equation
Now 
And 
(P) Now at t = 0.2 sec
The magnitude of the induced emf = E = Bv 
= 4xl.2x 
= 1.2Volt
(Q) At t = 0.2 sec, the magnitude of magnetic force = BI 
sin 
Newton
(R) At t = 0.2 sec, the power dissipated as heat
p = 0.144 watt
(S) Magnitude of terminal velocity
At terminal velocity, the net force become zero
V T = 2 m/s
Hence, Answer is
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