Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:
Text Solution
Verified by ExpertsGiven that,
Length of 1 st pendulum, l 1 =121 cm = 1.21 m
Length of 2 nd pendulum, l 2 =100 cm = 1.00 m
Now,
The equation for time period of a simple pendulum is
i.e 
As a result, we can conclude that after the 11 th oscillation of the shorter pendulum, it will be in phase with the longer pendulum,
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