How much 235 U is consumed in a day in an atomic powerhouse operating at 400 MW, provided the whole of the mass of 235 U is converted into energy ?
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Sol. Rate of production of energy
P = 400 MW = 400 × 10 6 J s –1
Energy produced in a day
E = P × 86400 J = 400 × 86400 × 10 6 J
= 3.456 × 10 13 J
If m kg is the required mass, then m = 
or m = 
kg = 0.384 × 10 –3 kg
= 0.384 g
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