Consider a metal scale of length 30 cm and an object. The scale is calibrated for temp 20ºC.
Text Solution
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λ = 1 {1 + 2 × 10 – 5 ×20}
λ = 10 {1 – 4 × 10 – 4 }
λ = 10 {1 + 4×10 – 4 }
% λ 1 = – 4 × 10 – 2 %
% λ 2 =
% ≈ – 4× 10 – 2 %
(e) λ 1 = 10 {1 + 20 × 4 × 10 – 5 }
λ 2 = 10 {1 – 20 × 4 × 10 – 5 }
(f) λ 1 = 10 {1 + 40 × 10 – 5 }
λ 2 = 10 {1 – 40 × 10 – 5 }
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