A satellite close to the earth is in orbit above the equator with a period of rotation of 1.5 hours. If it is above a point P on the equator at some time, it will be above P again after time
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(b, d)
Let ω ω 0 = the angular velocity of the earth about its axis.
24 = 
Let ω ω = the angular velocity of the satellite
1.5 = 
For a satellite rotating from west to east (the same as the earth), the relative angular velocity, ω ω 1 = ω ω - ω ω 0 .
Time period of rotation relative to the earth = 
= 1.6 h.
For a satellite rotating from east to west (opposite to the earth), the relative angular velocity, ω ω 2 = ω ω + ω ω 0 .
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