Published by:
CGP EDU Academic Team
Published on: September 12, 2026
In order to make the effective acceleration due to gravity equal to zero at the equator, the angular velocity of rotation of the earth about its axis should be $(g = 10ms^{-2}$ and radius of earth is 6400 kms)
$(a) 0 radsec^{-1} (b) \frac{1}{800} radsec^{-1} (c) \frac{1}{80} radsec^{-1} (d) \frac{1}{8} radsec^{-1}$
Text Solution
Verified by ExpertsThe correct answer is:
B
$g' = g - \omega^{2} R \cos^{2} \lambda$
For weightlessness at equator $\lambda = 0$ and g' = 0
∴ ∴ $0 = g - \omega^{2} R$ ⇒ ⇒ $\omega = \sqrt{\frac{g}{R}} = \frac{1}{800} \frac{\mathrm{rad}}{\mathrm{s}}$
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