A mercury drop shaped as round tablet of radius ‘ R ’ and thickness ‘ h ’ is located between two horizontal glass-plates . Assuming h << R, find the expression in weight which has placed on the upper plate to diminish the distance between the plates ‘ n ’ times . The angle of contact = 
. Calculate the weight if R = 2.0 cm, h = 0.38 mm, n = 2 and 
= 135º. Surface tension of Hg = 0.49 N/m.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(0.7 kg)
Sol. π R 2 h = π R 1 2 , 
R 1 = 
R
mg = → 
for balancing the plate
w + mg = 
→ for " plate + weight"
w = 
= 
= 
N
= 
kg
= 0.7 kg
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. (Surface…
A thin liquid film formed between a U-shaped wire and a light slider supports a weight of 1.5 × 10 …
Assume that a drop of liquid evaporates by decrease in its surface energy, so that its temperature …
Two mercury drops (each of radius ‘r’) merge to from bigger drop. The surface energy of the bigger …
A U-tube is made up of capillaries of bores 1 mm and 2 mm respectively. The tube is held vertically…
A film of soap solution is formed on a loop frame loop of 6.28 cm long thread is gently put on the …