Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Assume that a drop of liquid evaporates by decrease in its surface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible? The surface tension is T, density of liquid is ρ and L is its latent heat of vaporization.
Text Solution
Verified by ExpertsThe correct answer is:
D
When radius is decrease by dr
decrease in surface energy = Heat required for vaporization
(4 π rdr) × T × 2 = 4 π r 2 drL ρ ⇒
r = 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. (Surface…
A thin liquid film formed between a U-shaped wire and a light slider supports a weight of 1.5 × 10 …
Two mercury drops (each of radius ‘r’) merge to from bigger drop. The surface energy of the bigger …
A U-tube is made up of capillaries of bores 1 mm and 2 mm respectively. The tube is held vertically…
A film of soap solution is formed on a loop frame loop of 6.28 cm long thread is gently put on the …
What is the excess pressure inside a bubble of soap solution of radius 5.0 mm, given that the surfa…