A battery of 10 volt is connected to a resistance of 20 ohm through a variable resistance R, the amount of charge which has passed in the circuit in 4 minutes, if the variable resistance R is increased at the rate of 5 ohm/min.
A
120 coulomb
B
120 log e 2 coulomb
C
coulomb
D
coulomb
Text Solution
Verified by ExpertsThe correct answer is:
B
I = 
; dq = 12 V 
q = 12 V 
= 12 V (log e 40 – log e 20)
= 12 × × 10 × × log e 2
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The balancing length for a cell is 560 cm in a potentiometer experiment. When an external resistanc…
The series combination of two batteries, both of the same emf 10V, but different internal resistanc…
Four resistances of 15 Ω Ω , 12 Ω Ω , 4 Ω Ω and 10 Ω Ω respectively in cyclic order to form Wheatst…
Match the following:
The following table gives the lengths of four copper rods at the same temperat…
Match the statements in Column I with the current element in Column II
Column - IColumn - II(A)Curr…
A continuous beam of electrons emitted by a heating filament are accelerated in free space by an el…