Four resistances of 15 Ω Ω , 12 Ω Ω , 4 Ω Ω and 10 Ω Ω respectively in cyclic order to form Wheatstone's network. The resistance that is to be connected in parallel with the resistance of 10 Ω Ω to balance the network is ________ Ω Ω .
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(10 Ω Ω )
× 12 = 15 × 4
on solving
R = 10 Ω Ω
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