Match the thermodynamic processes given under Column- I with the expressions given under Column- II .
Column-I | Column-II | ||
(a) | Freezing of water at 273 K and 1 atm | (P) | q = 0 |
(b) | Expansion of 1 mol of an ideal gas into a vacuum under isolated conditions | (Q) | w = 0 |
(c) | Mixing of equal volumes of two ideal gases at constant temperature and pressure in an isolated container | (R) | ΔSsys < 0 |
(d) | Reversible heating of H2(g) at 1 atm from 300 K to 600 K, followed by reversible cooling to 300 K at 1 atm | (S) | ΔU = 0 |
(T) | ΔG = 0 |
Text Solution
Verified by ExpertsA
(A-R,T); (B-P,Q,S); (C-P,Q,S); (D-P,Q,S,T)
H 2 O( 
) ⎯→ H 2 O(s) at 273 K. & 1 atm
Δ H = – ve = q
Δ S sys < 0, Δ G = 0.
w ≠ 0 (as water expands on freezing), Δ U ≠ 0
Free expansion of ideal gas. q = 0
w = 0
Δ U = 0
Δ S sys > 0
Δ G < 0
Mixing of equal volume of ideal gases at constant pressure & temp in an isolated container
q = 0, w = 0, Δ U = 0, Δ S sys > 0, Δ G < 0
H 2 (g) 300 K 
600 K 
300 K.
q = 0, w = 0, Δ U = 0, Δ G = 0, Δ S sys = 0
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