Published by:
CGP EDU Academic Team
Published on: August 14, 2026
A gas ‘X’ is passed through water to form a saturated solution. The aqueous solution on treatment with silver nitrate gives a white precipitate. The saturated aqueous solution also dissolves magnesium ribbon with evolution of a colourless gas ‘Y’. Identify ‘X’ and ‘Y’.
Text Solution
Verified by ExpertsThe correct answer is:
C
Cl 2 (X) + H 2 O
HCl + HOCl ;
HCl + AgNO 3
AgCl ↓ (white) ' + HNO 3 ;
2HCl + Mg
MgCl 2 + H 2 (y)
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Highly pure dilute solution of sodium in liquid ammonia :
Sodium nitrate decomposes above 800°C to give :
Beryllium chloride shows acidic nature in water or why BeCl 2 is easily hydrolysed ?
The Haber's process can be represented by the following scheme :
Identify A, B, C, D and E.
A white solid is either Na 2 O or Na 2 O 2 . A piece of red litmus paper turns white when it is dip…
Identify the following :
Na 2 CO 3 A B C D
Also mention the oxidation state of S in all the com…