The reactions of Cl 2 gas with cold-dilute and hot-concentrated NaOH in water give sodium salts to two (different) oxoacids of chlorine, P and Q, respectively. The Cl 2 gas reacts with SO 2 gas, in presence of charcoal, to give a product R. R reacts with white phosphours to give a compound S. On hydrolysis, S gives an oxoacid of phosphours T.
(i) P and Q, respectively, are the sodium salts of :
Text Solution
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(i)a (ii)a
Sol. (i) & (ii)
Cl 2 + cold dil. NaOH 
NaOCl + NaCl
Cl 2 + hot conc. NaOH 
NaClO 3 + NaCl
NaOCl is salt of hypochlorous acid = P.
NaOCl 3 is salt of chloric acid = Q.
Cl 2 + SO 2 
SO 2 Cl 2 (R)
SO 2 Cl 2 + P 4 
PCl 5 (S) + SO 2
PCl 5 + H 2 O 
H 3 PO 4 (T) + HCl
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