The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by NiCl 2 .6H 2 O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl 2 .6H 2 O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____. (Atomic weights in g mol – 1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)
Text Solution
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2992
Sol. 
Number of Moles of (NH 4 ) 2 SO 4 = 
= 12 moles
Moles of NH 3 released = 24 moles
Moles of NiCl 2 .6H 2 O = 
= 4 moles
Number of moles of Gypsum (CaSO 4 .2H 2 O) formed = 12 moles
Mass of Gypsum formed = 12 × 172 = 2064
Number of moles of complex formed [Ni(NH 3 ) 6 ]Cl 2 = 
= 4 moles
Mass of complex formed = 4 × 232 = 928 g
Total Mass = 2064 + 928 = 2992 g
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